{
  "title": "sri answer 2",
  "taskId": "0b916cb2-a5e0-4add-a1d6-d2beba7276ec",
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            "text": "For a Dual active bridge converter operating under single-phase shift modulation, the average power transfer equation is defined as :"
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            "text": "                                                                   "
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                "text": "P_(av)=(V_(text(in))V_o  delta(1-delta))/(2nLf_(sw"
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            "text": "The given system parameters are defined as follows:"
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                        "text": "V_(i n)=450V"
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                        "text": "V_o=800V"
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                        "text": "L=100*10^-6H"
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                        "text": "f_(sw)=200*10^3"
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            "text": " "
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            "text": "Calculate the normalized duty ratio "
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            "text": "The physical phase shift is given as "
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                "text": "60^circ"
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            "text": ".  Normalize this against the maximum possible power-transfer phase angle shift of a half-cycle, which is 180 degrees:"
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                "text": "delta = 60^circ/180^circ"
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                "text": "= 1/3"
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            "text": "Determine the effective turns ratio "
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                "text": "(n)"
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        "content": [
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            "text": "The problem specifies a transformer turns ratio of 2:4 ("
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                "text": "N_p:N_s)"
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            "text": ". For this specific formulation, the turns ratio must scale the primary values to the secondary side :"
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                "text": "n = N_s/N_p"
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                "text": "= 4/2"
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                "text": "= 2"
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            "text": "Calculate the average power by substituting the values  ."
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                "text": "P_(av) = (V_(i n)V_odelta(1-delta))/(2nLf_(sw"
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            "content": [
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                "text": "= (800*450*1/3(1-1/3))/(.2*2*100*10^-6*200*10^3)"
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                "text": "= (360000*1/3*2/3)/(4*20"
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                "text": "= 80000/80"
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                "text": "P_(av = 1000W"
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            "text": "Convert the absolute power from watts into kilowatts (kW),"
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                "text": "P_(av)=(1000W)/1000=1kW"
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            "text": "The final answer is "
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